Example 1: Variables on both sides

Multi-step equations 1

Example 1: Variables on both sides

Discussion and questions for this video
Does anyone know why he divides by 13 in the end
It is because he wants to find the value of 1y, not 13y.
What if there are more than 1 "y" like 3 + 3y + 5y = 4 - 2y + 3y? Would you combine the y's?
you combine the y's to make the equation easier to work with, and so you can reduce messing up, and it takes less steps. does this help?
A coefficient is the number in front of a variable that tells how much of the variable is contained in the problem. For example, in the expression 2x, two is the coefficient. There are two x's, which can also be represented by x+x.
He divides both sides by -13 to come up with only one y on the left side. -13y = -26 is not the full answer that we need, we are looking to find what the value of only 1 (one) y is and that is why we need to divide both sides by -13.

You can also multiply both sides by -1\13 (multiplicative inverse of -13) and you will get the same answer !

Divide both sides by -13:
-13y = -26
-13y/-13 = -26/-13

or multiply both sides by -1\13:
-13y = -26
-1\13 * -13y = -26 * -1\13
So then he can get the y value by its self and your answer ends up being y=2
It's more confusing until you get used to it, but some write in the operations (say, adding 2x or dividing by 3) inside the existing line's equation. This becomes much more common at college level where no one wants to write 50 lines for simplifying to 10a -3b + 7c + 2x + 4y - 5z = 8 from where there's likely a bunch of variables on a side you don't want them to be. You just do several subtractions/additions at once and then divide the entire equation by the coefficient. It gets really burdensome when you're dealing with a dozen terms or more to do it one term at a time! If you want an actual example of doing multiple terms at once, I can probably find one for you or you can just look up precalc/trigonometry videos to see it in action.
How do you know or decide which side of the equation to put the variables on?
There is no difference whatsoever. Right or left works. Depends on what you are comfortable with. Generally you will move it to the left, unlike Sal did here, but either way's fine. Like Caroline said, you read left to right. Just do what you are comfortable with. Both sides will come out the same.
how do you know this all math? you are awsome and whats your name
24=-6x-18 (distributive property)
24=-6x-18 (isolating the variable)
+18 +18
42=-6x (to get (x) by itself)
/-6 /-6

Anthony is correct in his answer, but let me show you how he got it.

You would approach the problem as follows: First, add 6 to both sides. The equation now reads e/5 = -3. Next, multiply both sides by 5, which leaves us with e = -15.

I hope this was helpful!
No, variables can go on either side. Left side is preferred though, because you read left to right. Right or left, it doesn't matter, both will come out with the same answer.
Can't you not do the subtraction and just move numbers with or without variables to the other side? Would that not get you the answer as well? For example, with
20 - 7y = 6y-6, you could move -7y to the other side so that it becomes positive and equals 6y + 7y which also equals 13y. And then you could move -6 to the other side so it also becomes positive and adds up to 26. Then 26 = 13y is simplifiable into 2 = y. Is that not possible as well?
Yes, you can definitely "just move it to the other side and change the sign".

But when you do, what you are really doing is subtracting (or adding) the same thing to both sides, and then using the identity property of addition to make the expression subtracted from itself to become zero and disappear.

It is important to understand the concept of adding or subtracting the same thing from each side which allows the expressions on each side remain equal.

Once you fully comprehend the concept of doing the same thing to each side, you can then skip the intermediate steps and it will look like you just move the expression to the other side while reversing the sign.
whats the difference the algebra we learn in middle school and pre-algebra that we learn in high school
Pre Algebra you usually learn in Middle School. Algebra 1 you usually learn as a Freshmen or Sophmore.
At 0:22 do you have to add 7y or subtract 6y?
Can't you add 6 to both sides?
Yes, you can do either, add 7y to both sides or subtract 6y from both sides, it doesn't matter. If you subtract 6y instead of adding 7y you will get :
subtract 6y from both
subtract 20 from both sides.
divide both sides by -13
You would not add 6 to both sides, 6y is positive, you do the opposite operation when you move a number to the other side of the equation, you would subtract 6y from both sides.
A coefficient is the constant that is multiplied by a variable.
For example, in `2x + 7` the coefficient of x is 2
And in `x/5` the coefficient of x is ⅕
And in `6x + 7y` the coefficient of x is 6 and the coefficient of y is 7
It doesn't matter, for some people its easier for them to work out the problem if its on the left side. And some prefer it on the right side.
u may wanna spell that right "dat" sounds like a gangster speaking :)
do you have to always subtract with the first number before doing the other numbers?
No, adding 6y would not cancel out one of the y's or in other words a y variable would still be on both sides of the equation
It would be 20-y=12y-6 after adding 6y
yes.....its called transposition
it means that you can take term(6y is a term, so is -6) and move it to the other side of the equation., but you have to do the opposite operation with it.
eg: 20-7y=6y-6
hope that helped
How do you know which number to take away? For example, when Sal added 6 to the right side. How do you know to do it on that side? I'm really confused on this, please help!
because, -6+6=0.if we add some other to -6 it would give us some other no.
In what case in real life would we get a question with variables on two sides?
To change the equation so that there is only one y-expression.

He started with 20 - 7y = 6y - 6

Adding 7y to both sides makes 20 - 7y + 7y= 6y - 6 + 7y

(We know that the two sides are still equal to each other because has done the same thing to both sides.)

Simplifying, he gets 20 = 17y - 6

He chose to add 7y to both sides so that the left-hand side became 20, an expression not involving y.
Why would you start adding or subtracting on a certain side instead of the other? I get confused a lot for where i put the distributive variable and/or the symbol (- minus)when adding the opposite or even when you decide to multiply instead of divide or vice versa. Is there a rule for that? Say you have 7y+(-6y)+5 =7x+8x-4 i'm not sure if that would even work but it is just a example. *if using a certain law can you describe how that law is used with the problem and why you wouldn't use another law?
x or any letter is left, and non-letter is right, right?

Technically it doesn't matter. To solve for an unknown the unknown variable could be on the left or on the right, as long as when you are finished it's ISOLATED (or "all by itself"). x=3 is the same thing as 3=x (that's called 'the symmetric property of equality'), so if you happen to isolate the variable on the right, you are allowed to reverse the direction of the equality. And you don't even need to wait until you've isolated everything to do the switch. For example, if you have 23=4x+2 you could write 4x+2=23… that's that same "symmetric property of equality" at work.

Now that said, out of habit most people tend to move the unknown to the left side and everything else to the right side. I think it just sounds better to say "x=3" than to say "3=x," but really all you need to do is isolate the unknown on ONE side. It doesn't specifically have to be the LEFT (although most people do chose to put the letters on the left!).

But in general, your basic approach is correct. You've got to isolate the variable to solve for it.
*A number multiplied to a variable in an expression* is a coefficient.
For example in 5x + 2y + 3 = 0 , 5 is the coefficent of x and 2 is the coefficent of y.
were is this usefull in life what job does this beside math teacher
This is a question that comes up a lot, and there are many different answers. Here are just a few (not all mine, just general answers which are often given).

- If you want to do anything science related, you'll need math. Physics relies on very advanced mathematics. Biology? You need mathematical models. Computer Science? That's all number systems. Etc. Even if you want to study something other than the hard sciences, there's still a very good chance you'll encounter maths. History, psychology, sociology, and many others use statistical, mathematical methods to process data. Bottom line: if you want higher education, you're very likely to need maths. Certainly not everything you'll learn in high school, but at least some of it.

- Mathematics is all around us. To truly understand the world, we need to understand mathematics. Without mathematics, we would still be cavemen; we would not be able to build houses without having them fall down. We would certainly not have electricity, let alone computers.

- In modern society it is as important to know at least basic mathematics as it is to know how to read and write. If you don't know anything about maths, you would be very bad at handling money for example.

- Even if you really don't need maths itself (or, more probable, some part of maths) studying it helps you build your analytical skills - which will certainly come in handy in any job and life in general.

For (even) more answers and examples check out http://mathforum.org/dr.math/faq/faq.why.math.html and http://www.mathguide.com/issues/whymath.html.
i am still very confused about this topic. why would you go straight to adding 6 to cancel out the negative 6. shouldn't you take away positive six from the twenty to cancel out the negative six?
That's one way of looking at it. But it may not that obvious that what Sal did and what you're suggesting will yield exactly the same result.
For example
Sal did something like this
6y-6+6 = 6y
And you're suggesting that it should be
6y-6-(-6) = 6y
Notice that if you multiply the negative sign - with -6 it will yield +6 (since negative x negative= positive)
That's why:
6y-6-(-6) = 6y-6+6= 6y
How do you know which term to eliminate first, e.g 20 first or 7y.
It doesn't matter. Either way will give you the same answer:
20-7y = 6y -6
Eliminate 20 first:
20 -20 -7y = 6y - 6 -20
-7y = 6y -26
-7y - 6y = 6y - 6y -26
-13y = -26
-13y/(-13) = -26/(-13)
y = 2
Eliminate 7y first:
20-7y = 6y -6
20 -7y + 7y = 6y +7y -6
20 = 13y -6
20 +6 = 13y - 6 + 6
26 = 13y
26/13 = 13y/13
y = 2
What is the steps to solve equation that have variable on both sides
Say your expression is: 3x+20=8x-10
add ten to both sides: 3x+30=8x
minus 3x from both sides:30=5x
divide both sides by 5: 6=x or x=6
and your equation is solved.

Hope this helps
I need help with this equation on my hm it's A=1/2Bh someone please help me.
20-7y=6y-6 Step 1: +7y =+7y Simplify 20=13y-6 Step 2: +6=+6
Simplify: 26=13y Step 3: 26/13=13y/13 Simplify and you're done! y=2
IS there another way to do this that was not in this video?
yes.....its called transposition
it means that you can take term(6y is a term, so is -6) and move it to the other side of the equation., but you have to do the opposite operation with it.
eg: 20-7y=6y-6
hope that helped
At :54, wouldn't it be 20y, because you get rid of the seven and you're left with y?
No, it would just be 20. The 20 didn't have a y to begin with, did it? if it doesn't start out with a variable it won't acquire one later in the problem.
Just remember to keep the equation balanced. if you take away something from one side, take away from the other side too.
if you need more help just click on "comment" and ask.
Is there a certain side I should put the variable on? like which side would make solving the problem easier for me? (reference, 0:33)
You can isolate the variable on either side.
Just choose the side that looks easiest to you.
Ifyour final answer is 17 = x you can always reverse that to x = 17. They both mean the same thing. Equality is commutative.

I hope that helps.
Help! I still don't understand it, I tried watching the video five times already but still don't understand!!
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