Main content
Course: CAHSEE > Unit 1
Lesson 1: CAHSEE- CAHSEE practice: Problems 1-3
- CAHSEE practice: Problems 4-9
- CAHSEE practice: Problems 10-12
- CAHSEE practice: Problems 13-14
- CAHSEE practice: Problems 15-16
- CAHSEE practice: Problems 17-19
- CAHSEE practice: Problems 20-22
- CAHSEE practice: Problems 23-27
- CAHSEE practice: Problems 28-31
- CAHSEE practice: Problems 32-34
- CAHSEE practice: Problems 35-37
- CAHSEE practice: Problems 38-42
- CAHSEE practice: Problems 43-46
- CAHSEE practice: Problems 47-51
- CAHSEE practice: Problems 52-53
© 2024 Khan AcademyTerms of usePrivacy PolicyCookie Notice
CAHSEE practice: Problems 17-19
CAHSEE Practice: Problems 17-19. Created by Sal Khan.
Want to join the conversation?
- Prepping for GED, would this help/ any courses that would help?(6 votes)
- Im trying to prep for the GED class I have coming up will this help any?(3 votes)
- About problem 18. What is the chance that she will pull THE SAME S as the first time?(1 vote)
- If she replaces the "S," then there is one "S" that she needs to pull out the second time.
Since the two events are independent, one "S" out of all the letters is 1/10(2 votes)
- what is a scatterplot that is nonlinear?(1 vote)
- A scatter plot doesn't have to be linear. It would still be a scatter plot, like at3:40.(2 votes)
- How is this suppose to help me pass my GED?(1 vote)
- Any practice will help you pass the math portion of the GED. All standardized math tests are similar depending on the level of the test. CAHSEE and GED are similar because it is the basic level of math comprehension that a High School student should possess. Also, for more practice watch the SAT videos on Kahn Academy. If you understand these videos and do some practice you will easily pass the math portion of your GED exam. Good luck.(4 votes)
- Hey my name'd Shi😄 It's February 26th 2018, I'm practicing for my Language Arts/Writing test as well as my Math .Would this be the best practice tool to utilize for my up coming test ? 4/25/2018..(1 vote)
- Your mom so pay more for test if you want it.(2 votes)
- Good luck for your GED Test.
And here's a material to sharpen your GED preps.
GED Test For Dummies, Quick Prep Edition-For Dummies (2014).epub - 5.1 MB
http://www.anafile.com/jniialn1cu8g.html(1 vote) - Could this help me out on my ged? you should make videos like this but.. for the ged test.(1 vote)
- It would definitely help some, as well as other math subjects on here. You could probably even get a practice GED test from whatever state you are in, and use that to help you determine which areas to focus on most.(1 vote)
- I'e never seen a test so easy. I thought CAHSEE would be tougher than the SAT.(1 vote)
- Is the hiset test the same or close to the ged?(1 vote)
Video transcript
Problem 17: Michelle read a book
review and predicted that the number of girls who will
like the book will be more than twice the number of boys
who will like the book. So, she predicted that the girls
would be more than twice -- let me box it out -- more
than twice the number of boys who will like the book. Which table shows data that
supports her prediction? So essentially, we just need
to find one of the tables where the number of girls who
like the book, that's just this column right here -- the
number who like the book -- should be more than twice
the number of boys. Let's see the girls here is
40, the boys here are 35, there are more girls than boys,
but it's not more than twice the boys. The boys are 35. Twice the boys would be 70, and
girls is definitely not more than 70, so that's
not our answer. Let's just go here, well, here
the boys are more than the girls, which definitely isn't
going to be the case. We need a situation where the
girls are more than twice the number of boys. So that's not our situation,
because the girls are actually smaller than the boys here. Here we have 35 boys, if you
multiply that by 2, you would get 70 boys. So twice the boys is 70. And we see that the girls, at
80, are more than twice the boys at 70. So that is our choice. The girls are more than
twice the boys. And if you look here, the boys
and girls are even, so the girls are definitely not more
than twice the boys. So we know definitely,
that B is our answer. Go to the next page, Problem 18:
Anna has the letter tiles below in a bag. It's very interesting, it just
happens to spell out statistics. She reached in the bag,
and pulled out an S. She then put the tile
back in the bag. OK, so all of them are
still in the bag. If Anna randomly selects a tile
from the bag, what is the probability she will
select an S again? So this is a trick question on
some level, because this first part, that she reached in the
bag and pulled out an S and she then put the tile
back in the bag. That doesn't do anything! The fact that she pulled out an
S, and then put it back in the bag, that shouldn't change
what happens afterward. If she took out the S and kept
the S out, then this would be a different type of problem. But since she took out the S
and put it back in, this is almost useless information. We still have all of these
letters in the bag. It says if Anna randomly selects
a tile from the bag, what is the probability
she'll select an S? So all we have to say is, all
of these are in the bag, so what are the possible
outcomes? So there's 1, 2, 3, 4, 5, 6, 7,
8, 9, 10 possible outcomes. 10 possible outcomes, so
that's going to be the denominator for our
probability. And then, what are the outcomes
that satisfy our conditions? Or, what are the outcomes
where she selects an S? She selects an S, so there's
1 S, 2 S, and 3 S's. There's 3 out of the 10
situations involve selecting an S, so the answer is 3/10. And the reason why I said it's
a trick question, is because they write statement which
really doesn't change the problem it all. She took out an S,
she put it back. If she said that she took out an
S, and then she did not put it back in the bag, then you
would say, oh gee, then there's only 9 tiles left; and
only two of them are S's, and then you would have said 2/9. But since she did put the S back
in the bag, we could say, oh, there's 10 letters in the
bag, 3 of them are S's, so the answer is 3/10. Problem 19: The scatterplot
below shows the ages of some children and the distance
each lives from school. So this is the ages, and
then this is the distance in that axis. Which statement best describes
the relation between age and distance from the school? Just looking at this, I really
don't see any relation, it seems to be fairly random. Let's see what the statements
tell us. As age and increases, the distance from school increases. No, not really, I mean,
that would look something like this. So this is our age axis, this
is our distance axis, what A is describing is as age
increases, the distance from school increases. The data points should look
something like this. They should generally increase
-- distance should generally increase as age increases. That's not what we see here,
I mean this really kind of seems arbitrary. It's not like this nice
upward trend. B, as age increases the distance from school decreases. Well I don't even see a downward
trend either, what B is describing, the data
would look like this. Where we have this
downward trend. I don't see that here, either. C, as age increases,
the distance from school remains constant. What C is describing
would have data that looks like this. That regardless of age, the
distance from school is about the same. I don't really see
that either. There's still a huge spread
of distances. And then D, there is no
relationship between the age and distance from school. I'll go with that one because,
you could imagine, if I tried to draw trend line, I could
draw something like that, maybe that makes it look
like there's a trend. But I just as easily could
have drawn that. And looks just is good to me. Or I just as easily could
have drawn that. None of these look like it
fits the data any better. So, at least the answer that I
feel comfortable with is D.